Hi

I am curently testing the adaptative partitionning

I wrote the following test program. It does the following tasks
Try to create a partition
If already created lookup for id
Joint the partition
Consume CPU (while loop) 

#include <sys/sched_aps.h>	// sched_aps_partition_info
#include <sys/neutrino.h>	// SchedCtl
#include <stdlib.h>
#include <string.h>
#include <errno.h>
#include <stdio.h>
#include <unistd.h>	// usleep
int main(void) {

	_Int16t id = 0;
	// create a partition
	sched_aps_create_parms creation_data;
	memset(&creation_data, 0, sizeof(creation_data));
	creation_data.budget_percent = 15;
	creation_data.critical_budget_ms = 0;
	creation_data.name = "DebugReserve";
	// Ne peut etre appelle qu'une fois avec un nom donne
	int ret = SchedCtl( SCHED_APS_CREATE_PARTITION, &creation_data,	sizeof(creation_data));
	if (ret != EOK)
	{
		printf("Couldn t create partition \"%s\": %s (%d).\n", creation_data.name, strerror(errno), errno);
		// already created

		sched_aps_lookup_parms lookup_data;
		memset(&lookup_data , 0 , sizeof ( lookup_data ) ) ;
		lookup_data.name = "DebugReserve";

		int ret = SchedCtl(SCHED_APS_LOOKUP, &lookup_data, sizeof(lookup_data) );
		if (EOK != ret)
		{
			printf("err SchedCtl SCHED_APS_LOOKUP ret %d errno %d %s\n",ret, errno, sys_errlist[errno]);
		}
		else
		{
			//use output field
			printf("SchedCtl SCHED_APS_LOOKUP OK id %d\n", lookup_data.id);
			id = lookup_data.id;
		}
	}
	else
	{
		printf ("The new partition ID is %d.\n", creation_data.id);
		id = creation_data.id;
	}

	sched_aps_join_parms join_data;
	memset(&join_data, 0, sizeof(join_data));
	join_data.id = id;
	join_data.pid = 0;
	join_data.tid = 0;
	ret = SchedCtl( SCHED_APS_JOIN_PARTITION, &join_data, sizeof(join_data));
	if (ret != EOK)
	{
		printf("Couldn’t join partition %d: %s (%d).\n",
				join_data.id, strerror(errno), errno);
	}
	else
	{
		printf ("Process is now in partition %d.\n", join_data.id);
	}
	// Consume max CPU
	while(1)
	{
		//usleep(1);
	}

	return 0;
}

I run both 3 instance of this program

if execute: aps show -v
the display is

                    +----------- CPU Time ------------+-- Critical Time --
                    |        |           Used         |        |
Partition name   id | Budget | 0.100s   1.00s   10.0s | Budget |      Used
--------------------+---------------------------------+-------------------
System            0 |    85% |  0.13%   0.07%   0.23% |  400ms |   0.000ms
DebugReserve      1 |    15% | 74.04%  73.37%  64.13% |    0ms |   0.000ms
--------------------+---------------------------------+-------------------
Total               |   100% | 74.17%  73.44%  64.36% |

The budget for the "DebugReserve" partition is 15% but the program overrun the budget of 15%
what is the problem, the code or my reasoning ?